Albany, Pepin County, Wisconsin
Albany is a town located in
Pepin County, Wisconsin. As of the
2000 census, the town had a total population of 620.
Geography
\nAccording to the United States Census Bureau, the town has a total area of 93.3
km² (36.0
mi²). 93.3 km² (36.0 mi²) of it is land and none of the area is covered with water.
Demographics
\nAs of the census2 of
2000, there are 620 people, 180 households, and 156 families residing in the town. The
population density is 6.6/km² (17.2/mi²). There are 189 housing units at an average density of 2.0/km² (5.2/mi²). The racial makeup of the town is 97.90% White, 0.00%
African American, 0.00%
Native American, 0.00%
Asian, 0.32% Pacific Islander, 0.32% from other races, and 1.45% from two or more races. 0.32% of the population are
Hispanic or
Latino of any race.
There are 180 households out of which 43.9% have children under the age of 18 living with them, 78.9% are married couples living together, 6.1% have a female householder with no husband present, and 12.8% are non-families. 10.0% of all households are made up of individuals and 4.4% have someone living alone who is 65 years of age or older. The average household size is 3.44 and the average family size is 3.75.
In the town the population is spread out with 37.9% under the age of 18, 8.2% from 18 to 24, 26.5% from 25 to 44, 20.6% from 45 to 64, and 6.8% who are 65 years of age or older. The median age is 28 years. For every 100 females there are 107.4 males. For every 100 females age 18 and over, there are 105.9 males.
The median income for a household in the town is $40,313, and the median income for a family is $41,375. Males have a median income of $26,023 versus $21,250 for females. The per capita income for the town is $13,012. 25.9% of the population and 14.6% of families are below the poverty line. Out of the total people living in poverty, 45.6% are under the age of 18 and 6.5% are 65 or older.