Aubrey, Arkansas
Aubrey is a town located in
Lee County, Arkansas. As of the
2000 census, the town had a total population of 221.
Geography
\nAubrey is located at 34°43'5" North, 90°53'58" West (34.718058, -90.899507)1.
According to the
United States Census Bureau, the town has a total area of 0.9
km² (0.3
mi²). 0.9 km² (0.3 mi²) of it is land and none of it is covered by water.
Demographics
\nAs of the census2 of
2000, there are 221 people, 92 households, and 59 families residing in the town. The
population density is 251.0/km² (641.7/mi²). There are 103 housing units at an average density of 117.0/km² (299.1/mi²). The racial makeup of the town is 67.87%
White, 30.32%
Black or
African American, 0.00%
Native American, 0.00%
Asian, 0.00%
Pacific Islander, 1.81% from
other races, and 0.00% from two or more races. 4.07% of the population are
Hispanic or
Latino of any race.
There are 92 households out of which 26.1% have children under the age of 18 living with them, 54.3% are married couples living together, 10.9% have a female householder with no husband present, and 34.8% are non-families. 32.6% of all households are made up of individuals and 21.7% have someone living alone who is 65 years of age or older. The average household size is 2.40 and the average family size is 3.12.
In the town the population is spread out with 27.1% under the age of 18, 6.3% from 18 to 24, 18.1% from 25 to 44, 24.9% from 45 to 64, and 23.5% who are 65 years of age or older. The median age is 43 years. For every 100 females there are 63.7 males. For every 100 females age 18 and over, there are 69.5 males.
The median income for a household in the town is $19,167, and the median income for a family is $19,167. Males have a median income of $20,250 versus $16,111 for females. The per capita income for the town is $11,805. 18.0% of the population and 15.2% of families are below the poverty line. Out of the total people living in poverty, 21.1% are under the age of 18 and 18.8% are 65 or older.