Belgrade, Nebraska
Belgrade is a village located in
Nance County, Nebraska. As of the
2000 census, the village had a total population of 134.
Geography
\nBelgrade is located at 41°28'17" North, 98°4'2" West (41.471327, -98.067302)1.
According to the
United States Census Bureau, the village has a total area of 0.5
km² (0.2
mi²). 0.5 km² (0.2 mi²) of it is land and none of it is covered by water.
Demographics
\nAs of the census of
2000, there are 134 people, 63 households, and 36 families residing in the village. The
population density is 287.4/km² (730.3/mi²). There are 77 housing units at an average density of 165.2/km² (419.6/mi²). The racial makeup of the village is 100.00% White, 0.00%
African American, 0.00%
Native American, 0.00%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.00% from two or more races. 0.00% of the population are
Hispanic or
Latino of any race.
There are 63 households out of which 23.8% have children under the age of 18 living with them, 47.6% are married couples living together, 4.8% have a female householder with no husband present, and 41.3% are non-families. 38.1% of all households are made up of individuals and 15.9% have someone living alone who is 65 years of age or older. The average household size is 2.13 and the average family size is 2.73.
In the village the population is spread out with 23.9% under the age of 18, 6.7% from 18 to 24, 22.4% from 25 to 44, 28.4% from 45 to 64, and 18.7% who are 65 years of age or older. The median age is 42 years. For every 100 females there are 94.2 males. For every 100 females age 18 and over, there are 92.5 males.
The median income for a household in the village is $28,750, and the median income for a family is $32,143. Males have a median income of $28,750 versus $21,875 for females. The per capita income for the village is $12,767. 15.8% of the population and 12.5% of families are below the poverty line. Out of the total people living in poverty, 0.0% are under the age of 18 and 33.3% are 65 or older.