Then ak converges cubically against 1/π; that is, each iteration approximately triples the number of correct digits.
Then pk converges quartically against π; that is, each iteration approximately quadruples the number of correct digits. The algorithm is not self-correcting; each iteration must be performed with the desired number of correct digits of π.
Then ak converges quintically against 1/π (that is, each iteration approximately quintuples the number of correct digits), and the following condition holds:
Then ak converges nonically against 1/π; that is, each iteration approximately multiplies the number of correct digits by nine.