Cumberland, Indiana
Cumberland is a town located in
Hancock County, Indiana. As of the
2000 census, the town had a total population of 5,500.
Geography
\nCumberland is located at 39°47'1" North, 85°57'8" West (39.783528, -85.952308)1.
According to the
United States Census Bureau, the town has a total area of 5.0
km² (1.9
mi²). 4.9 km² (1.9 mi²) of it is land and 0.1 km² (0.04 mi²) of it is water. The total area is 1.55% water.
Demographics
\nAs of the census of
2000, there are 5,500 people, 2,030 households, and 1,565 families residing in the town. The
population density is 1,123.6/km² (2,907.0/mi²). There are 2,190 housing units at an average density of 447.4/km² (1,157.5/mi²). The racial makeup of the town is 85.20% White, 10.56%
African American, 0.22%
Native American, 1.76%
Asian, 0.04% Pacific Islander, 0.75% from other races, and 1.47% from two or more races. 1.45% of the population are
Hispanic or
Latino of any race.
There are 2,030 households out of which 40.6% have children under the age of 18 living with them, 59.3% are married couples living together, 14.6% have a female householder with no husband present, and 22.9% are non-families. 19.1% of all households are made up of individuals and 5.7% have someone living alone who is 65 years of age or older. The average household size is 2.70 and the average family size is 3.08.
In the town the population is spread out with 30.0% under the age of 18, 7.1% from 18 to 24, 29.9% from 25 to 44, 24.4% from 45 to 64, and 8.6% who are 65 years of age or older. The median age is 34 years. For every 100 females there are 92.5 males. For every 100 females age 18 and over, there are 88.1 males.
The median income for a household in the town is $57,875, and the median income for a family is $61,739. Males have a median income of $48,750 versus $28,239 for females. The per capita income for the town is $24,746. 6.6% of the population and 5.0% of families are below the poverty line. Out of the total people living in poverty, 12.2% are under the age of 18 and 1.5% are 65 or older.