Table of contents |
2 Counterexample 3 Explanation via Lebesgue theory 4 In the positive sense |
A double integral
Definitions
is defined via a 2-dimensional measure in the plane, rather than by integrating twice (see Lebesgue integral).
On the other hand, if we define
Does it matter whether one integrates first with respect to x and then with respect to y or vice-versa?
Perhaps surprisingly, in some cases yes, as an example shows:
Counterexample
Obviously the sign gets reversed if the order of iterated integration gets reversed, i.e., if "dy dx" replaces "dx dy". But the value of the integral is not zero, and so the values of the two iterated integrals differ from each other. For the details of the evaluation of this integral, see an elegant rearrangement of a conditionally convergent iterated integral.
To give the analytic explanation: the double integral exists only if
Explanation via Lebesgue theory
and in that case, the double integral coincides in value with either of the two iterated integrals. Thus, whenever the two iterated integrals differ in value from each other, the double integral of the absolute value of the function must be infinite. See Fubini's theorem.
One can give a further explanation, however from the other direction, based on the special role of functions f(x)g(y).
These, in which the roles of the two variables are uncoupled, present no problem in this context; and neither do their linear combinations. Quite generally, given compact spaces X and Y, we can use the Stone-Weierstrass theorem to show that such functions give a subalgebra of C(X×Y) that is dense in the uniform norm: or in other words any continuous function on X×Y can be uniformly approximated by sums of functions f(x)g(y).
This implies that double integrals behave rather well, at least on a large collection of 'test' functions.In the positive sense