Floyd, Iowa
Floyd is a city located in
Floyd County, Iowa. As of the
2000 census, the city had a total population of 361.
Geography
\nFloyd is located at 43°7'39" North, 92°44'23" West (43.127494, -92.739628)1.
According to the
United States Census Bureau, the city has a total area of 1.5
km² (0.6
mi²). 1.5 km² (0.6 mi²) of it is land and none of it is covered by water.
Demographics
\nAs of the census of
2000, there are 361 people, 142 households, and 102 families residing in the city. The
population density is 236.2/km² (612.7/mi²). There are 147 housing units at an average density of 96.2/km² (249.5/mi²). The racial makeup of the city is 99.17% White, 0.00%
African American, 0.00%
Native American, 0.55%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.28% from two or more races. 0.00% of the population are
Hispanic or
Latino of any race.
There are 142 households out of which 33.1% have children under the age of 18 living with them, 62.0% are married couples living together, 4.2% have a female householder with no husband present, and 27.5% are non-families. 23.2% of all households are made up of individuals and 11.3% have someone living alone who is 65 years of age or older. The average household size is 2.54 and the average family size is 2.99.
In the city the population is spread out with 24.4% under the age of 18, 9.4% from 18 to 24, 23.8% from 25 to 44, 29.4% from 45 to 64, and 13.0% who are 65 years of age or older. The median age is 40 years. For every 100 females there are 108.7 males. For every 100 females age 18 and over, there are 99.3 males.
The median income for a household in the city is $35,096, and the median income for a family is $36,458. Males have a median income of $28,021 versus $18,438 for females. The per capita income for the city is $14,723. 6.4% of the population and 3.1% of families are below the poverty line. Out of the total people living in poverty, 10.6% are under the age of 18 and 12.5% are 65 or older.