Grover, Wyoming
Grover is a town located in
Lincoln County, Wyoming. As of the
2000 census, the town had a total population of 137.
Geography
\nGrover is located at 42°47'35" North, 110°55'55" West (42.793051, -110.931862)1.
According to the
United States Census Bureau, the town has a total area of 2.2
km² (0.9
mi²). 2.2 km² (0.9 mi²) of it is land and none of the area is covered with water.
Demographics
\nAs of the census of
2000, there are 137 people, 48 households, and 38 families residing in the town. The
population density is 61.5/km² (159.0/mi²). There are 56 housing units at an average density of 25.1/km² (65.0/mi²). The racial makeup of the town is 96.35% White, 0.00%
African American, 0.00%
Native American, 0.73%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 2.92% from two or more races. 2.92% of the population are
Hispanic or
Latino of any race.
There are 48 households out of which 43.8% have children under the age of 18 living with them, 79.2% are married couples living together, 0.0% have a female householder with no husband present, and 20.8% are non-families. 20.8% of all households are made up of individuals and 12.5% have someone living alone who is 65 years of age or older. The average household size is 2.85 and the average family size is 3.32.
In the town the population is spread out with 27.7% under the age of 18, 15.3% from 18 to 24, 20.4% from 25 to 44, 25.5% from 45 to 64, and 10.9% who are 65 years of age or older. The median age is 36 years. For every 100 females there are 101.5 males. For every 100 females age 18 and over, there are 102.0 males.
The median income for a household in the town is $32,500, and the median income for a family is $34,250. Males have a median income of $29,375 versus $20,625 for females. The per capita income for the town is $15,687. 0.0% of the population and 0.0% of families are below the poverty line.