Hay Springs, Nebraska
Hay Springs is a village located in
Sheridan County, Nebraska. As of the
2000 census, the village had a total population of 652.
Geography
\nHay Springs is located at 42°40'59" North, 102°41'22" West (42.683099, -102.689469)1.
According to the
United States Census Bureau, the village has a total area of 1.0
km² (0.4
mi²). 1.0 km² (0.4 mi²) of it is land and none of it is covered by water.
Demographics
\nAs of the census of
2000, there are 652 people, 283 households, and 181 families residing in the village. The
population density is 662.5/km² (1,715.2/mi²). There are 334 housing units at an average density of 339.4/km² (878.6/mi²). The racial makeup of the village is 90.18% White, 0.00%
African American, 5.67%
Native American, 0.00%
Asian, 0.00% Pacific Islander, 1.53% from other races, and 2.61% from two or more races. 2.30% of the population are
Hispanic or
Latino of any race.
There are 283 households out of which 25.4% have children under the age of 18 living with them, 53.0% are married couples living together, 7.4% have a female householder with no husband present, and 35.7% are non-families. 31.8% of all households are made up of individuals and 18.7% have someone living alone who is 65 years of age or older. The average household size is 2.29 and the average family size is 2.90.
In the village the population is spread out with 22.4% under the age of 18, 8.7% from 18 to 24, 21.5% from 25 to 44, 24.7% from 45 to 64, and 22.7% who are 65 years of age or older. The median age is 44 years. For every 100 females there are 90.6 males. For every 100 females age 18 and over, there are 82.7 males.
The median income for a household in the village is $30,078, and the median income for a family is $34,318. Males have a median income of $30,000 versus $21,136 for females. The per capita income for the village is $14,376. 12.5% of the population and 10.3% of families are below the poverty line. Out of the total people living in poverty, 16.8% are under the age of 18 and 8.9% are 65 or older.