Henry, South Dakota
Henry is a town located in
Codington County, South Dakota. As of the
2000 census, the town had a total population of 268.
Geography
\nHenry is located at 44°52'40" North, 97°27'57" West (44.877650, -97.465968)1.
According to the
United States Census Bureau, the town has a total area of 3.8
km² (1.5
mi²). 3.8 km² (1.5 mi²) of it is land and none of the area is covered with water.
Demographics
\nAs of the census of
2000, there are 268 people, 101 households, and 71 families residing in the town. The
population density is 71.4/km² (185.3/mi²). There are 116 housing units at an average density of 30.9/km² (80.2/mi²). The racial makeup of the town is 98.88% White, 0.00%
African American, 0.37%
Native American, 0.00%
Asian, 0.00% Pacific Islander, 0.75% from other races, and 0.00% from two or more races. 1.87% of the population are
Hispanic or
Latino of any race.
There are 101 households out of which 37.6% have children under the age of 18 living with them, 57.4% are married couples living together, 9.9% have a female householder with no husband present, and 29.7% are non-families. 26.7% of all households are made up of individuals and 9.9% have someone living alone who is 65 years of age or older. The average household size is 2.65 and the average family size is 3.28.
In the town the population is spread out with 28.7% under the age of 18, 8.6% from 18 to 24, 31.7% from 25 to 44, 21.3% from 45 to 64, and 9.7% who are 65 years of age or older. The median age is 32 years. For every 100 females there are 111.0 males. For every 100 females age 18 and over, there are 103.2 males.
The median income for a household in the town is $36,607, and the median income for a family is $42,500. Males have a median income of $24,167 versus $25,750 for females. The per capita income for the town is $13,778. 10.0% of the population and 5.1% of families are below the poverty line. Out of the total people living in poverty, 10.0% are under the age of 18 and 38.5% are 65 or older.