Lake Harbor, Florida
Lake Harbor is a town located in
Palm Beach County, Florida. As of the
2000 census, the town had a total population of 195.
Geography
\nLake Harbor is located at 26°41'13" North, 80°48'27" West (26.686985, -80.807613)1.
According to the
United States Census Bureau, the town has a total area of 3.4
km² (1.3
mi²). 3.4 km² (1.3 mi²) of it is land and none of it is covered by water.
Demographics
\nAs of the census of
2000, there are 195 people, 65 households, and 44 families residing in the town. The
population density is 57.5/km² (148.7/mi²). There are 118 housing units at an average density of 34.8/km² (90.0/mi²). The racial makeup of the town is 41.54% White, 42.56%
African American, 0.00%
Native American, 3.08%
Asian, 0.00% Pacific Islander, 2.05% from other races, and 10.77% from two or more races. 6.67% of the population are
Hispanic or
Latino of any race.
There are 65 households out of which 32.3% have children under the age of 18 living with them, 50.8% are married couples living together, 12.3% have a female householder with no husband present, and 32.3% are non-families. 24.6% of all households are made up of individuals and 4.6% have someone living alone who is 65 years of age or older. The average household size is 3.00 and the average family size is 3.55.
In the town the population is spread out with 29.2% under the age of 18, 5.1% from 18 to 24, 32.8% from 25 to 44, 22.6% from 45 to 64, and 10.3% who are 65 years of age or older. The median age is 39 years. For every 100 females there are 105.3 males. For every 100 females age 18 and over, there are 106.0 males.
The median income for a household in the town is $35,208, and the median income for a family is $31,250. Males have a median income of $36,458 versus $16,250 for females. The per capita income for the town is $12,977. 9.7% of the population and 0.0% of families are below the poverty line. Out of the total people living in poverty, 0.0% are under the age of 18 and 0.0% are 65 or older.