If α1,...,αn are distinct algebraic numbers, and β1,...,βn are any nonzero algebraic numbers, then
The transcendence of e and &pi are direct corollaries of this theorem. To show the transcendence of e, note that if e were algebraic, there would exist rational_numbers β0,...,βn, not all zero, such that
To show the transcendence of π, suppose that π was algebraic. Since the set of all algebraic numbers forms a field, this implies that πi and 2πi are also algebraic. Taking β1 = β2 = 1, α1 = πi, α2 = 2πi, the Lindemann-Weierstrass theorem gives us the equation (see Euler's formula)
The theorem is named for Carl Louis Ferdinand von Lindemann and Karl Weierstraß