Lizton, Indiana
Lizton is a town located in
Hendricks County, Indiana. As of the
2000 census, the town had a total population of 372.
Geography
\nLizton is located at 39°53'7" North, 86°32'39" West (39.885274, -86.544207)1.
According to the
United States Census Bureau, the town has a total area of 0.8
km² (0.3
mi²). 0.8 km² (0.3 mi²) of it is land and none of it is covered by water.
Demographics
\nAs of the census of
2000, there are 372 people, 161 households, and 100 families residing in the town. The
population density is 495.3/km² (1,303.3/mi²). There are 180 housing units at an average density of 239.6/km² (630.6/mi²). The racial makeup of the town is 98.39% White, 0.27%
African American, 0.00%
Native American, 0.00%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 1.34% from two or more races. 0.00% of the population are
Hispanic or
Latino of any race.
There are 161 households out of which 37.9% have children under the age of 18 living with them, 44.1% are married couples living together, 11.8% have a female householder with no husband present, and 37.3% are non-families. 33.5% of all households are made up of individuals and 11.2% have someone living alone who is 65 years of age or older. The average household size is 2.31 and the average family size is 2.94.
In the town the population is spread out with 26.9% under the age of 18, 7.8% from 18 to 24, 36.3% from 25 to 44, 18.8% from 45 to 64, and 10.2% who are 65 years of age or older. The median age is 33 years. For every 100 females there are 96.8 males. For every 100 females age 18 and over, there are 94.3 males.
The median income for a household in the town is $40,694, and the median income for a family is $55,313. Males have a median income of $36,023 versus $23,750 for females. The per capita income for the town is $20,269. 3.1% of the population and 3.0% of families are below the poverty line. Out of the total people living in poverty, 1.5% are under the age of 18 and 3.6% are 65 or older.