Oakley, Utah
Oakley is a city located in
Summit County, Utah. As of the
2000 census, the city had a total population of 948.
Geography
\nOakley is located at 40°43'7" North, 111°17'16" West (40.718595, -111.287863)1.
According to the
United States Census Bureau, the city has a total area of 16.3
km² (6.3
mi²). 16.3 km² (6.3 mi²) of it is land and none of the area is covered with water.
Demographics
\nAs of the census of
2000, there are 948 people, 278 households, and 232 families residing in the city. The
population density is 58.1/km² (150.5/mi²). There are 330 housing units at an average density of 20.2/km² (52.4/mi²). The racial makeup of the city is 96.41% White, 0.11%
African American, 0.21%
Native American, 0.21%
Asian, 0.00% Pacific Islander, 2.95% from other races, and 0.11% from two or more races. 4.32% of the population are
Hispanic or
Latino of any race.
There are 278 households out of which 48.2% have children under the age of 18 living with them, 74.5% are married couples living together, 6.5% have a female householder with no husband present, and 16.5% are non-families. 10.8% of all households are made up of individuals and 4.3% have someone living alone who is 65 years of age or older. The average household size is 3.41 and the average family size is 3.74.
In the city the population is spread out with 36.8% under the age of 18, 8.3% from 18 to 24, 28.7% from 25 to 44, 19.9% from 45 to 64, and 6.2% who are 65 years of age or older. The median age is 32 years. For every 100 females there are 107.9 males. For every 100 females age 18 and over, there are 102.4 males.
The median income for a household in the city is $61,250, and the median income for a family is $62,059. Males have a median income of $41,250 versus $30,625 for females. The per capita income for the city is $21,855. 2.3% of the population and 1.6% of families are below the poverty line. Out of the total people living in poverty, 2.6% are under the age of 18 and 0.0% are 65 or older.