Osceola, Nebraska
Osceola is a city located in
Polk County, Nebraska. As of the
2000 census, the city had a total population of 921. It is the
county seat of
Polk County6.
Geography
\nOsceola is located at 41°10'41" North, 97°32'55" West (41.177957, -97.548732)1.
According to the
United States Census Bureau, the city has a total area of 2.3
km² (0.9
mi²). 2.3 km² (0.9 mi²) of it is land and none of it is covered by water.
Demographics
\nAs of the census of
2000, there are 921 people, 381 households, and 235 families residing in the city. The
population density is 399.6/km² (1,036.8/mi²). There are 417 housing units at an average density of 180.9/km² (469.4/mi²). The racial makeup of the city is 99.57% White, 0.00%
African American, 0.33%
Native American, 0.00%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.11% from two or more races. 0.43% of the population are
Hispanic or
Latino of any race.
There are 381 households out of which 27.3% have children under the age of 18 living with them, 54.9% are married couples living together, 5.8% have a female householder with no husband present, and 38.1% are non-families. 36.7% of all households are made up of individuals and 23.6% have someone living alone who is 65 years of age or older. The average household size is 2.27 and the average family size is 2.99.
In the city the population is spread out with 23.8% under the age of 18, 5.4% from 18 to 24, 23.6% from 25 to 44, 20.8% from 45 to 64, and 26.4% who are 65 years of age or older. The median age is 43 years. For every 100 females there are 80.2 males. For every 100 females age 18 and over, there are 78.2 males.
The median income for a household in the city is $34,737, and the median income for a family is $46,354. Males have a median income of $33,906 versus $19,432 for females. The per capita income for the city is $17,037. 6.8% of the population and 5.2% of families are below the poverty line. Out of the total people living in poverty, 10.7% are under the age of 18 and 3.2% are 65 or older.