Poland, Herkimer County, New York
Poland is a village located in
Herkimer County, New York. As of the
2000 census, the village had a total population of 451.
Geography
\nPoland is located at 43°13'34" North, 75°3'41" West (43.226178, -75.061521)1.
According to the
United States Census Bureau, the village has a total area of 1.4
km² (0.5
mi²). 1.4 km² (0.5 mi²) of it is land and 1.85% is water.
Demographics
\nAs of the census of
2000, there are 451 people, 192 households, and 126 families residing in the village. The
population density is 322.5/km² (842.2/mi²). There are 202 housing units at an average density of 144.4/km² (377.2/mi²). The racial makeup of the village is 96.67% White, 0.22%
African American, 0.00%
Native American, 2.66%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.44% from two or more races. 2.00% of the population are
Hispanic or
Latino of any race.
There are 192 households out of which 28.1% have children under the age of 18 living with them, 53.6% are married couples living together, 9.9% have a female householder with no husband present, and 33.9% are non-families. 28.6% of all households are made up of individuals and 14.6% have someone living alone who is 65 years of age or older. The average household size is 2.35 and the average family size is 2.84.
In the village the population is spread out with 23.7% under the age of 18, 7.5% from 18 to 24, 27.1% from 25 to 44, 25.3% from 45 to 64, and 16.4% who are 65 years of age or older. The median age is 39 years. For every 100 females there are 94.4 males. For every 100 females age 18 and over, there are 88.0 males.
The median income for a household in the village is $38,750, and the median income for a family is $45,455. Males have a median income of $27,426 versus $22,159 for females. The per capita income for the village is $17,938. 11.1% of the population and 8.5% of families are below the poverty line. Out of the total people living in poverty, 18.9% are under the age of 18 and 0.0% are 65 or older.