Robertson, Wyoming
Robertson is a town located in
Uinta County, Wyoming. As of the
2000 census, the town had a total population of 59.
Geography
\nRobertson is located at 41°11'24" North, 110°25'46" West (41.190095, -110.429333)1.
According to the
United States Census Bureau, the town has a total area of 8.1
km² (3.1
mi²). 8.1 km² (3.1 mi²) of it is land and none of the area is covered with water.
Demographics
\nAs of the census of
2000, there are 59 people, 23 households, and 18 families residing in the town. The
population density is 7.3/km² (19.0/mi²). There are 36 housing units at an average density of 4.5/km² (11.6/mi²). The racial makeup of the town is 96.61% White, 0.00%
African American, 0.00%
Native American, 0.00%
Asian, 0.00% Pacific Islander, 0.00% from other races, and 3.39% from two or more races. 0.00% of the population are
Hispanic or
Latino of any race.
There are 23 households out of which 26.1% have children under the age of 18 living with them, 73.9% are married couples living together, 8.7% have a female householder with no husband present, and 17.4% are non-families. 13.0% of all households are made up of individuals and 4.3% have someone living alone who is 65 years of age or older. The average household size is 2.57 and the average family size is 2.84.
In the town the population is spread out with 25.4% under the age of 18, 3.4% from 18 to 24, 16.9% from 25 to 44, 28.8% from 45 to 64, and 25.4% who are 65 years of age or older. The median age is 48 years. For every 100 females there are 90.3 males. For every 100 females age 18 and over, there are 91.3 males.
The median income for a household in the town is $52,750, and the median income for a family is $31,875. Males have a median income of $21,875 versus $36,250 for females. The per capita income for the town is $17,432. 7.9% of the population and 10.5% of families are below the poverty line. Out of the total people living in poverty, 0.0% are under the age of 18 and 25.0% are 65 or older.