Severance Township, Minnesota

Severance Township is a township located in Sibley County, Minnesota. As of the 2000 census, the township had a total population of 343.

Geography

\nAccording to the United States Census Bureau, the township has a total area of 98.6 km² (38.1 mi²). 94.5 km² (36.5 mi²) of it is land and 4.1 km² (1.6 mi²) of it is water. The total area is 4.15% water.

Demographics

\nAs of the census of 2000, there are 343 people, 119 households, and 96 families residing in the township. The population density is 3.6/km² (9.4/mi²). There are 123 housing units at an average density of 1.3/km² (3.4/mi²). The racial makeup of the township is 97.38% White, 0.29% African American, 0.00% Native American, 0.29% Asian, 0.00% Pacific Islander, 0.87% from other races, and 1.17% from two or more races. 1.17% of the population are Hispanic or Latino of any race. There are 119 households out of which 43.7% have children under the age of 18 living with them, 69.7% are married couples living together, 3.4% have a female householder with no husband present, and 19.3% are non-families. 16.8% of all households are made up of individuals and 6.7% have someone living alone who is 65 years of age or older. The average household size is 2.88 and the average family size is 3.24. In the township the population is spread out with 29.2% under the age of 18, 8.5% from 18 to 24, 26.2% from 25 to 44, 23.3% from 45 to 64, and 12.8% who are 65 years of age or older. The median age is 36 years. For every 100 females there are 117.1 males. For every 100 females age 18 and over, there are 129.2 males. The median income for a household in the township is $39,063, and the median income for a family is $45,625. Males have a median income of $26,750 versus $27,500 for females. The per capita income for the township is $14,857. 4.6% of the population and 5.6% of families are below the poverty line. Out of the total people living in poverty, 0.0% are under the age of 18 and 16.3% are 65 or older.