Wilson, Wyoming
Wilson is a town located in
Teton County, Wyoming. As of the
2000 census, the town had a total population of 1,294.
Geography
\nWilson is located at 43°29'11" North, 110°52'45" West (43.486300, -110.879279)1.
According to the
United States Census Bureau, the town has a total area of 60.3
km² (23.3
mi²). 59.9 km² (23.1 mi²) of it is land and 0.4 km² (0.2 mi²) of it is water. The total area is 0.69% water.
Demographics
\nAs of the census of
2000, there are 1,294 people, 563 households, and 305 families residing in the town. The
population density is 21.6/km² (56.0/mi²). There are 706 housing units at an average density of 11.8/km² (30.5/mi²). The racial makeup of the town is 97.68% White, 0.08%
African American, 0.15%
Native American, 0.46%
Asian, 0.00% Pacific Islander, 0.54% from other races, and 1.08% from two or more races. 1.00% of the population are
Hispanic or
Latino of any race.
There are 563 households out of which 25.2% have children under the age of 18 living with them, 47.6% are married couples living together, 3.7% have a female householder with no husband present, and 45.8% are non-families. 28.6% of all households are made up of individuals and 2.7% have someone living alone who is 65 years of age or older. The average household size is 2.27 and the average family size is 2.86.
In the town the population is spread out with 20.9% under the age of 18, 4.3% from 18 to 24, 39.1% from 25 to 44, 28.3% from 45 to 64, and 7.4% who are 65 years of age or older. The median age is 37 years. For every 100 females there are 117.1 males. For every 100 females age 18 and over, there are 120.0 males.
The median income for a household in the town is $65,327, and the median income for a family is $93,354. Males have a median income of $30,455 versus $61,635 for females. The per capita income for the town is $65,489. 6.4% of the population and 0.0% of families are below the poverty line. Out of the total people living in poverty, 0.0% are under the age of 18 and 0.0% are 65 or older.