Zerbe Township, Pennsylvania

Zerbe Township is a township located in Northumberland County, Pennsylvania. As of the 2000 census, the township had a total population of 2,021.

Geography

\nAccording to the United States Census Bureau, the township has a total area of 30.0 km² (11.6 mi²). 30.0 km² (11.6 mi²) of it is land and 0.09% is water.

Demographics

\nAs of the census of 2000, there are 2,021 people, 871 households, and 561 families residing in the township. The population density is 67.3/km² (174.4/mi²). There are 946 housing units at an average density of 31.5/km² (81.6/mi²). The racial makeup of the township is 98.71% White, 0.15% African American, 0.05% Native American, 0.15% Asian, 0.00% Pacific Islander, 0.15% from other races, and 0.79% from two or more races. 0.40% of the population are Hispanic or Latino of any race. There are 871 households out of which 25.3% have children under the age of 18 living with them, 52.4% are married couples living together, 8.4% have a female householder with no husband present, and 35.5% are non-families. 31.8% of all households are made up of individuals and 16.5% have someone living alone who is 65 years of age or older. The average household size is 2.32 and the average family size is 2.92. In the township the population is spread out with 21.2% under the age of 18, 7.0% from 18 to 24, 27.6% from 25 to 44, 23.8% from 45 to 64, and 20.3% who are 65 years of age or older. The median age is 42 years. For every 100 females there are 100.5 males. For every 100 females age 18 and over, there are 95.1 males. The median income for a household in the township is $31,964, and the median income for a family is $38,000. Males have a median income of $30,236 versus $18,207 for females. The per capita income for the township is $15,780. 8.6% of the population and 6.0% of families are below the poverty line. Out of the total people living in poverty, 7.8% are under the age of 18 and 13.5% are 65 or older.